Question

(3-2a) +(4-3a)+(5-5a)=12+7a=

Answer 1

Ответ:

(3-2a)+(4-3a)+(5-5a)=3-2a+4-3a+5-5a=12-10a

Answer 2

To solve the equation (3-2a) + (4-3a) + (5-5a) = 12 + 7a, follow these steps:

1. First, simplify both sides of the equation by combining like terms:

   (3 - 2a) + (4 - 3a) + (5 - 5a) = 12 + 7a

   Combine the constants on the left side:

   (3 + 4 + 5) - (2a + 3a + 5a) = 12 + 7a

   12 - 10a = 12 + 7a

2. Now, isolate the variable terms on one side and the constant terms on the other side. To do this, you can add 10a to both sides of the equation:

   12 - 10a + 10a = 12 + 7a + 10a

   12 = 12 + 17a

3. Subtract 12 from both sides to isolate the variable term:

   12 - 12 = 12 + 17a - 12

   0 = 17a

4. Finally, solve for 'a' by dividing both sides by 17:

   0/17 = 17a/17

   0 = a

So, the solution to the equation is a = 0.