Question

56:х=(10+6):2 х-340:10=12:2

Answer 1

Ответ:

$1)56:x=(10+6):2\\56:x=16:2\\56:x=8\\x=56:8\\x=7$

$2)x-340:10=12:2\\x-34=12:2\\x-34=6\\x=6+34\\x=40$

Пошаговое объяснение:

Answer 2

Let's solve this system of equations step by step:

1. Start with the first equation: 56:х=(10+6):2 To simplify this equation, first, calculate the values inside the parentheses and the division on the right side:

   56/х = (10+6)/2

   Now, simplify further:

   56/х = 16/2

   56/х = 8

   To solve for х, you can cross-multiply:

   56 = 8х

   Now, divide both sides by 8 to isolate х:

   56/8 = х

   7 = х

2. Move on to the second equation: х-340:10=12:2 First, simplify the right side:

   х - 340/10 = 12/2

   х - 34 = 6

   Now, isolate х by adding 34 to both sides of the equation:

   х - 34 + 34 = 6 + 34

   х = 40

So, the solution to the system of equations is х = 7 and х = 40. However, these two values are not equal, which means there is no single solution that satisfies both equations simultaneously. The system of equations is inconsistent.