Question

C(4;2;-3) D(-2;2;5). CD=?​

Answer 1

ОТВЕТ:

СD(-6;0;8)

Решение

СD=(-2-(-4); 2-2; 5-(-3))=(-6; 0; 8)

Answer 2

To find the distance between points C(4, 2, -3) and D(-2, 2, 5), you can use the distance formula, which is derived from the Pythagorean theorem in three dimensions. The distance formula is:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$

In your case, C is the point (x1, y1, z1) and D is the point (x2, y2, z2). Plug in the values:

$$\begin{align*} x_1 &= 4 \\ y_1 &= 2 \\ z_1 &= -3 \\ x_2 &= -2 \\ y_2 &= 2 \\ z_2 &= 5 \\ \end{align*}$$

Now, calculate the distance:

$$\begin{align*} d &= \sqrt{(-2 - 4)^2 + (2 - 2)^2 + (5 - (-3))^2} \\ d &= \sqrt{(-6)^2 + (0)^2 + (8)^2} \\ d &= \sqrt{36 + 0 + 64} \\ d &= \sqrt{100} \\ d &= 10 \end{align*}$$

So, the distance between points C(4, 2, -3) and D(-2, 2, 5) is 10 units.