Question

6 3/16-(2 3/8+3 5/12)=

Answer 1

Пошаговое объяснение:

6 3/16-(2 3/8+3 5/12)=

99/16-(19/8+41/12)=99/16-(57+82)/24=

=99/16-139/24= (297-278)/48=19/48

Answer 2

To solve the expression $6 \frac{3}{16} - (2 \frac{3}{8} + 3 \frac{5}{12})$, follow these steps:

1. Convert mixed numbers to improper fractions:

   $6 \frac{3}{16} = \frac{(6 \times 16) + 3}{16} = \frac{99}{16}$

   $2 \frac{3}{8} = \frac{(2 \times 8) + 3}{8} = \frac{19}{8}$

   $3 \frac{5}{12} = \frac{(3 \times 12) + 5}{12} = \frac{41}{12}$

2. Perform operations inside the parentheses:

   $2 \frac{3}{8} + 3 \frac{5}{12} = \frac{19}{8} + \frac{41}{12}$

   To add these fractions, find a common denominator, which is 24.

   $\frac{19}{8} \times \frac{3}{3} = \frac{57}{24}$

   $\frac{41}{12} \times \frac{2}{2} = \frac{82}{24}$

   $\frac{57}{24} + \frac{82}{24} = \frac{139}{24}$

3. Subtract the result from step 2 from $\frac{99}{16}$:

   $\frac{99}{16} - \frac{139}{24}$

   To subtract, find a common denominator, which is 48.

   $\frac{99}{16} \times \frac{3}{3} = \frac{297}{48}$

   $\frac{297}{48} - \frac{139}{24}$

   Multiply the numerator and denominator of $\frac{139}{24}$ by 2 to make the denominators the same.

   $\frac{297}{48} - \frac{278}{48}$

4. Subtract the numerators and keep the common denominator:

   $\frac{297 - 278}{48} = \frac{19}{48}$

So, $6 \frac{3}{16} - (2 \frac{3}{8} + 3 \frac{5}{12}) = \frac{19}{48}$.