Question

(x^2-x-2)(x^2-3x-18)=16x^2 Нужно решить, срочно, помогите пожалуйста

Answer 1

Ну приступим-с (x + 1)(x - 2)(x + 3)(x - 6) = 16x^2 - теорема Виета или через D; Группируем 1-ую скобку с 4-ой, 2-ую с 3-ей: (x^2 - 6 - 5x)(x^2 - 6 + x) = 16x^2 Далее делим правую и левую части на x^2 (x - 6/x - 5)(x -6/x + 1) = 16 Замена t = x - 6/x Получается: (t - 5)(t + 1) = 16 t^2 - 4t - 5 - 16 = 0 t^2 - 4t - 21 = 0 t = - 4 | t = 7 x^2 - 6 + 4x = 0 | x^2- 6 - 7x = 0 иксы сам найдешь

Answer 2

Solving the Equation

To solve the given equation (x^2-x-2)(x^2-3x-18)=16x^2, we can start by expanding the left-hand side of the equation and then simplifying it.

Expanding the equation: (x^2-x-2)(x^2-3x-18) = 16x^2 Expanding the left-hand side gives: x^4 - 3x^3 - 18x^2 - x^3 + 3x^2 + 18x - 2x^2 + 6x + 36 = 16x^2 Simplifying the left-hand side further: x^4 - 4x^3 - x^2 + 24x + 36 = 16x^2 x^4 - 4x^3 - 17x^2 + 24x + 36 = 16x^2

Now, we have the equation in the form: x^4 - 4x^3 - 17x^2 + 24x + 36 - 16x^2 = 0 x^4 - 4x^3 - 33x^2 + 24x + 36 = 0

We can proceed to solve this equation.

Further Steps

To solve the equation x^4 - 4x^3 - 33x^2 + 24x + 36 = 0, we can use various methods such as factoring, the rational root theorem, or numerical methods. However, due to the complexity of the equation, it may not have simple rational roots.

Given the complexity of the equation, it may be best to use numerical methods or a graphing calculator to find the approximate solutions for x. If you have specific values for x that you'd like to solve for, please provide them so that I can assist you further.

Feel free to provide more details or specific values for x, and I can help you with the next steps in solving this equation.