Question

28+3, 3y+1, 07y=71, 7

Answer 1

Ответ:

Пошаговое объяснение:

28+3,3y+1,07y=71, 7

4,37у=71,7-28

4,37у=43,7

у=43,7:4,37

у=10

28+3,3*10+1,07*10=71,7

71,7=71,7

Answer 2

It seems like you've written a set of mathematical expressions and equations. Let's break it down step by step:

1. 28 + 3: The sum of 28 and 3 is 31.

2. 3y + 1: This is an algebraic expression. It represents "three times y plus one."

3. 07y = 71: This is an algebraic equation. It seems like you're trying to solve for y. Let's solve it:

   Subtract 1 from both sides to isolate the term with y: $07y = 71 - 1$ $07y = 70$

   Now, divide both sides by 7 to solve for y: $y = \frac{70}{7}$ $y = 10$

So, the solutions are:

• $28 + 3 = 31$
• $y = 10$ (from the given equation $07y = 71$)