Question

Log(1,2)32-log(1,2)16=

Answer 1

Решение:

Если нужно упростить выражение,

то решение такое:

log(1,2)32 - log(1,2)16 = log(1,2)32/16 = log(1,2)2.

Если в основании логарифма не 1,2, а число 1/2, о решение такое:

log(1/2)32 - log(1/2)16 = log(1/2) (32/16) = log(1/2)2 = - 1.

Answer 2

To simplify the expression:

log₂(32) - log₂(16)

You can use the properties of logarithms, specifically the subtraction rule, which states that:

log_b(x) - log_b(y) = log_b(x/y)

In your case:

log₂(32) - log₂(16) = log₂(32/16)

Now, calculate 32/16:

32/16 = 2

So, the expression simplifies to:

log₂(2)

The base-2 logarithm of 2 is equal to 1, because 2 to the power of 1 equals 2:

log₂(2) = 1

So, the final answer is 1.