Question

(7-х)(3х-9)(13х-52)=0

Answer 1

Ответ:

3; 4; 7

Пошаговое объяснение:

произведение равно нулю, если один из множителей равен нулю:

7-x=0; -x=-7 |*(-1); x=7

3x-9=0; 3x=9 |:3; x=3

13x-52=0; 13x=52 |:13; x=4

Answer 2

Ответ:

х1=7

х2=3

х3=4

Пошаговое объяснение:

(7-х)(3х-9)(13х-52)=0

Если пример равен нулю, тогда один из множителей равен нулю.

рассмотрим первый множитель:

7-х=0

х=0+7

х=7

второй:

3х-9=0

3х=9

х=9:3

х=3

третий:

13х-52=0

13х=52

х=52:13

х=4

Answer 3

To solve the equation (7-х)(3х-9)(13х-52) = 0, you can use the zero-product property, which states that if the product of several factors is equal to zero, then at least one of the factors must be equal to zero.

So, in this case, you have:

(7-х)(3х-9)(13х-52) = 0

Now, set each factor equal to zero and solve for x:

1. 7 - x = 0 Subtract 7 from both sides: -x = -7 Divide both sides by -1 to isolate x: x = 7

2. 3x - 9 = 0 Add 9 to both sides: 3x = 9 Divide both sides by 3 to isolate x: x = 3

3. 13x - 52 = 0 Add 52 to both sides: 13x = 52 Divide both sides by 13 to isolate x: x = 4

So, the solutions to the equation are x = 7, x = 3, and x = 4.