Question

1) 3/5(5b-2/3)<b+7,6 2) 8(6-y)<24,2-7y ​

Answer 1

Ответ:

только 1

Пошаговое объяснение:

Answer 2

To solve the inequalities, let's work through them one by one:

1. $\frac{3}{5}(5b-\frac{2}{3}) < b + 7$

First, distribute $\frac{3}{5}$ to both terms inside the parentheses:

$3b - \frac{6}{5} < b + 7$

Now, let's isolate the variable $b$. Start by subtracting $b$ from both sides:

$2b - \frac{6}{5} < 7$

Next, add $\frac{6}{5}$ to both sides:

$2b < 7 + \frac{6}{5}$

Now, simplify the right side:

$2b < \frac{35}{5} + \frac{6}{5}$

$2b < \frac{41}{5}$

Finally, divide both sides by 2 to isolate $b$:

$b < \frac{41}{5} \div 2$

$b < \frac{41}{10}$

So, the solution for the first inequality is:

$b < \frac{41}{10}$

2. $8(6 - y) < 24 - 2(7y)$

First, distribute 8 to both terms inside the parentheses on the left side:

$48 - 8y < 24 - 14y$

Next, add $14y$ to both sides to collect the $y$ terms on the right side:

$48 + 6y < 24$

Now, subtract 48 from both sides:

$6y < 24 - 48$

$6y < -24$

Finally, divide both sides by 6 to isolate $y$:

$y < \frac{-24}{6}$

$y < -4$

So, the solution for the second inequality is:

$y < -4$