Question

|х+3|=10 (х+2):(х-1)=0

Answer 1

Відповідь:

1. 7, -13; 2. -2;

Покрокове пояснення:

1.

$|x+3|=10\\\\x+3 = 10\\x+3=-10\\\\x_{1} =7, x_{2} =-13$

2.

$></p> <p>Щоб розв'язати рівняння, потрібно чисельник прирівняти до 0.</p> <p>x + 2 = 0</p> <p>x = -2</p> <p></p> </div> <div class=$ 0 0

Answer 2

Let's solve the given equations step by step.

1. |x + 3| = 10

To solve this equation, you need to consider two cases: one where the expression inside the absolute value is positive and one where it's negative.

Case 1 (x + 3 is positive): x + 3 = 10 x = 10 - 3 x = 7

Case 2 (x + 3 is negative): -(x + 3) = 10 x + 3 = -10 x = -10 - 3 x = -13

So, for the first equation, you have two solutions: x = 7 and x = -13.

2. (x + 2) / (x - 1) = 0

To solve this equation, you need to find the values of x that make the fraction equal to 0. For a fraction to be equal to 0, the numerator (x + 2) must be equal to 0, and the denominator (x - 1) must not be equal to 0.

Numerator: x + 2 = 0 x = -2

Denominator: x - 1 ≠ 0 x ≠ 1

So, the solution for the second equation is x = -2, but x cannot be equal to 1.

Therefore, the solutions for the system of equations are: For the first equation: x = 7 and x = -13 For the second equation: x = -2 (while x cannot be equal to 1).