Question

8sin(-45°)+tg45°-2cos(-60°)=?​

Answer 1

Пошаговое объяснение:

надеюсь мой почерк понятен

Answer 2

Let's calculate the expression step by step:

1. Start with the first term: 8sin(-45°).

   Since sine is an odd function (sin(-x) = -sin(x)), we have:

   8sin(-45°) = 8 * (-sin(45°))

   Now, sin(45°) is equal to √2/2, so:

   8 * (-sin(45°)) = 8 * (-√2/2) = -4√2

2. Move on to the second term: tg45° (tangent of 45°).

   The tangent of 45° is 1.

3. Finally, let's calculate the third term: -2cos(-60°).

   Again, since cosine is an even function (cos(-x) = cos(x)), we have:

   -2cos(-60°) = -2 * cos(60°)

   Now, cos(60°) is equal to 1/2, so:

   -2 * cos(60°) = -2 * (1/2) = -1

Now, let's put it all together:

-4√2 + 1 - 1 = -4√2

So, the final result is:

8sin(-45°) + tg45° - 2cos(-60°) = -4√2.