Question

A)y- 7/12 y = 4 1/6 б)х-9/16х=5 1/4​

Answer 1

Ответ:

вот надеюсь помогла)))

Answer 2

It looks like you have two linear equations, one with the variable "y" and the other with the variable "x." Let's solve them step by step.

A) $y - \frac{7}{12}y = 4 \frac{1}{6}$

To solve for "y," you can first combine the terms on the left side of the equation:

$\frac{5}{12}y = 4 \frac{1}{6}$

Now, you want to isolate "y" by multiplying both sides of the equation by the reciprocal of $\frac{5}{12}$, which is $\frac{12}{5}$:

$y = 4 \frac{1}{6} \times \frac{12}{5}$

Now, calculate the right side of the equation:

$y = \frac{49}{5}$

So, the solution for $y$ is $y = \frac{49}{5}$.

B) $x - \frac{9}{16}x = 5 \frac{1}{4}$

To solve for "x," you can first combine the terms on the left side of the equation:

$\frac{7}{16}x = 5 \frac{1}{4}$

Now, you want to isolate "x" by multiplying both sides of the equation by the reciprocal of $\frac{7}{16}$, which is $\frac{16}{7}$:

$x = 5 \frac{1}{4} \times \frac{16}{7}$

Now, calculate the right side of the equation:

$x = \frac{85}{7}$

So, the solution for $x$ is $x = \frac{85}{7}$.