Question

(x+1):(y-3)=8:3 3y=36

Answer 1

Ответ:

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Пошаговое объяснение:

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Answer 2

Ответ:

y= 36:12

y= 3

(x+1):(3-3)=8:3

x+1 : 0 = 8:3

x +1 = 8:3*0

x+1=0

x= 0-1

x=-1

Answer 3

To solve the equations $\frac{x+1}{y-3} = \frac{8}{3}$ and $3y = 36$, you can follow these steps:

Step 1: Solve for $y$ in the second equation $3y = 36$:

Divide both sides by 3 to isolate $y$:

$\frac{3y}{3} = \frac{36}{3}$ $y = 12$

Now that we have found the value of $y$, which is $y = 12$, we can substitute this into the first equation to solve for $x$:

Step 2: Substitute $y = 12$ into the first equation $\frac{x+1}{y-3} = \frac{8}{3}$:

$\frac{x+1}{12-3} = \frac{8}{3}$

Simplify the denominator:

$\frac{x+1}{9} = \frac{8}{3}$

Now, to get rid of the fraction on the right-hand side, multiply both sides of the equation by 9:

$9 \left(\frac{x+1}{9}\right) = 9 \left(\frac{8}{3}\right)$

The 9 on the left cancels out with the 9 in the denominator:

$x + 1 = 24$

Now, isolate $x$ by subtracting 1 from both sides:

$x = 24 - 1$ $x = 23$

So, the solution to the system of equations is $x = 23$ and $y = 12$.