Question

(y+4,5):7=1,2 41-7,08y=23,3 21,71+4.06y=27,8 5,09х-3,84х=1 3,4+1.8х=43,16

Answer 1

1. (у+4.5)= 8.4
у=3.9
2. 4.06у=6.09
у= 1.5
3.1.25х=1
х=0.8

Answer 2

It looks like you've provided a system of linear equations. Let's solve these equations one by one:

1. $\frac{y+4}{5} = \frac{7}{1}$

To solve this equation, you can cross-multiply:

$1(y + 4) = 7(5)$

$y + 4 = 35$

Now, subtract 4 from both sides:

$y = 35 - 4$

$y = 31$

So, the solution to the first equation is $y = 31$.

2. $41 - 7.08y = 23.3$

Subtract 23.3 from both sides:

$41 - 23.3 - 7.08y = 0.7$

Now, subtract 41 from both sides:

$-7.08y = -17.3$

To isolate y, divide both sides by -7.08:

$y = \frac{-17.3}{-7.08}$

$y \approx 2.448$

So, the solution to the second equation is approximately $y \approx 2.448$.

3. $21.71 + 4.06y = 27.8$

Subtract 21.71 from both sides:

$4.06y = 27.8 - 21.71$

$4.06y = 6.09$

Now, divide both sides by 4.06 to isolate y:

$y = \frac{6.09}{4.06}$

$y \approx 1.5$

So, the solution to the third equation is approximately $y \approx 1.5$.

4. $5.09x - 3.84x = 1$

Subtract 3.84x from 5.09x:

$1.25x = 1$

Now, divide both sides by 1.25 to isolate x:

$x = \frac{1}{1.25}$

$x = 0.8$

So, the solution to the fourth equation is $x = 0.8$.

5. $3.4 + 1.8x = 43.16$

Subtract 3.4 from both sides:

$1.8x = 43.16 - 3.4$

$1.8x = 39.76$

Now, divide both sides by 1.8 to isolate x:

$x = \frac{39.76}{1.8}$

$x \approx 22.09$

So, the solution to the fifth equation is approximately $x \approx 22.09$.

To summarize:

1. $y = 31$
2. $y \approx 2.448$
3. $y \approx 1.5$
4. $x = 0.8$
5. $x \approx 22.09$