Question

1) 7(2x+9)+3x=114 2) 3(4x+13)-25=74

Answer 1

7(2x+9)+3x=114
14x+63+3x=114
17x=114-63
x=51:17
x=3

3(4x+13)-25=74
12x+39-25=74
12x=74-14
x=60:12
x=5

Answer 2

7(2х+9)+3х=114
14х+63+3х=114
17х=114-63
17х=51
х=51:17
х=3

3(4х+13)-25=74
12х+39-25=74
12х=74+25-39
12х=60
х=60:12
х=5

Answer 3

It looks like you've provided two algebraic equations. If you're looking to solve for the variable 'x' in each equation, I can help you with that. Let's solve these equations step by step:

Equation 1: 7(2x + 9) + 3x = 114

First, distribute the 7 on the left side: 14x + 63 + 3x = 114

Combine the x terms: 17x + 63 = 114

Now, isolate the x term by subtracting 63 from both sides: 17x = 51

Divide by 17: x = 51 / 17 x = 3

So, the solution for Equation 1 is x = 3.

Equation 2: 3(4x + 13) - 25 = 74

First, distribute the 3 on the left side: 12x + 39 - 25 = 74

Combine the constant terms: 12x + 14 = 74

Now, isolate the x term by subtracting 14 from both sides: 12x = 60

Divide by 12: x = 60 / 12 x = 5

So, the solution for Equation 2 is x = 5.

In both cases, x represents the value that satisfies the given equations.