Question

1)3(х-2)=х+2 2)5-2(х-1)=4-х

Answer 1

3(x-2)=x+2
3x-6=x+2
3x-x=2+6
2x=8
x=4

5-2(x-1)=4-x
5-2x-2=4-x
5-2-4=2x-x
x=-1

Answer 2

Sure, I'd be happy to help you solve these equations:

1. $3(x-2) = x+2$

Let's start by distributing the 3 on the left side of the equation:

$3x - 6 = x + 2$

Now, let's move all the terms containing $x$ to one side and the constants to the other side:

Subtract $x$ from both sides:

$3x - x - 6 = 2$

Simplify:

$2x - 6 = 2$

Now, add 6 to both sides:

$2x = 8$

Finally, divide both sides by 2:

$x = 4$

So, the solution for the first equation is $x = 4$.

2. $5 - 2(x-1) = 4 - x$

Again, distribute the -2 on the left side:

$5 - 2x + 2 = 4 - x$

Simplify:

$7 - 2x = 4 - x$

Now, let's move all the terms containing $x$ to one side and the constants to the other side:

Subtract $4$ from both sides:

$7 - 2x - 4 = -x$

Simplify:

$3 - 2x = -x$

Now, add $2x$ to both sides:

$3 = x$

So, the solution for the second equation is $x = 3$.

To summarize:

1. $x = 4$
2. $x = 3$