Question

3x-11x -4=0 x^2-3х+1=0

Answer 1

3x-11x-4=0
-8х=4
х=-4/8=-1/2=-0.5

х^2-3х+1=0
D=9-4*1=1
х1=(3+1)/2=2
х2=(3-1)/2=1

Answer 2

It seems like you have provided two equations. The first one appears to be a linear equation, while the second one is a quadratic equation. Let's solve them step by step:

1. 3x - 11x - 4 = 0: Combine like terms on the left side: -8x - 4 = 0

Now, add 4 to both sides: -8x = 4

Divide by -8: x = -0.5

So, the solution for the first equation is x = -0.5.

2. x^2 - 3x + 1 = 0: This is a quadratic equation. You can solve it using the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

For the equation x^2 - 3x + 1 = 0: a = 1, b = -3, and c = 1.

Plug the values into the formula: x = (3 ± √((-3)^2 - 4 * 1 * 1)) / (2 * 1) x = (3 ± √(9 - 4)) / 2 x = (3 ± √5) / 2

So, the solutions for the quadratic equation are: x = (3 + √5) / 2 x = (3 - √5) / 2

These are the two solutions for the quadratic equation.

To summarize:

1. Solution for the first equation: x = -0.5
2. Solutions for the second equation: x = (3 + √5) / 2 and x = (3 - √5) / 2