Question

-6x^2-12xy-6y^2 x=2 2/5,y=0,6

Answer 1

2 целых 2/5 = 2,4
-6х² - 12ху - 6у² = -6(х² + 2ху + у²) = -6(х + у)²
при х = 2,4 и у = 0,6    -6(2,4 + 0,6)² = -6 · 3² = -6 · 9 = -54

Answer 2

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Answer 3

To find the value of the expression -6x^2-12xy-6y^2 when x = 2 2/5 and y = 0.6, we need to substitute these values into the expression and then perform the calculations.

First, let's convert the mixed number 2 2/5 to an improper fraction:

2 2/5 = 12/5

Now, substitute the values of x and y into the expression:

-6(12/5)^2 - 12(12/5)(0.6) - 6(0.6)^2

Now, let's perform the calculations step by step:

1. Calculate (12/5)^2:

(12/5)^2 = (144/25)

2. Calculate 12(12/5)(0.6):

12(12/5)(0.6) = 12 * 12/5 * 0.6 = 144/5 * 0.6 = 144/5 * 3/5 = (144 * 3)/(5 * 5) = 432/25

3. Calculate (-6)(0.6)^2:

(-6)(0.6)^2 = (-6) * (0.6)^2 = (-6) * (0.36) = -2.16

Now, add up all the calculated parts:

-6(144/25) - 432/25 - 2.16

Now, let's convert the constants to fractions:

-6(144/25) = -864/25

Now, add all the fractions together:

(-864/25) - (432/25) - (216/100)

Now, find a common denominator for the fractions:

The common denominator for 25 and 100 is 100:

(-864/25) - (432/25) - (216/100) = (-86400/2500) - (43200/2500) - (216/100)

Now, add the fractions together:

(-86400 - 43200 - 5400)/2500

Calculate the numerator:

(-134400)/2500 = -5376

Finally, the result of the expression when x = 2 2/5 and y = 0.6 is:

-5376/2500, which is approximately -2.15 when rounded to two decimal places.