Question

Решите уравнения:1)216\y=12,2)948\y-12

Answer 1

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Answer 2

To solve the equations, we need to find the value of 'y' that satisfies each equation.

1. $\frac{216}{y} = 12$

To solve for 'y', we can isolate 'y' on one side of the equation.

Step 1: Multiply both sides of the equation by 'y' to get rid of the denominator:

$y \times \frac{216}{y} = y \times 12$

Step 2: On the left side, 'y' cancels out with the denominator, leaving:

$216 = 12y$

Step 3: Now, divide both sides by 12 to isolate 'y':

$y = \frac{216}{12}$

$y = 18$

So the solution for the first equation is $y = 18$.

2. $\frac{948}{y} - 12$

It seems there's a missing equals sign in the second equation. I assume the equation should be:

$\frac{948}{y} = 12$

To solve for 'y', follow the same steps as before:

Step 1: Multiply both sides of the equation by 'y':

$y \times \frac{948}{y} = y \times 12$

Step 2: On the left side, 'y' cancels out with the denominator, leaving:

$948 = 12y$

Step 3: Now, divide both sides by 12 to isolate 'y':

$y = \frac{948}{12}$

$y = 79$

So the solution for the second equation is $y = 79$.