
[X^2+12x+64]=[x^2-64]


Ответы на вопрос

12х + 128 = 0
12х = -128
х = -128/12 = -32/3 = -10⅔
Ответ: -10⅔



To solve the equation [X^2 + 12x + 64] = [x^2 - 64], we need to find the values of x that satisfy the equation.
Let's start by expanding the expressions within the brackets:
[X^2 + 12x + 64] = X^2 + 12x + 64 [x^2 - 64] = x^2 - 64
Now, we have the equation:
X^2 + 12x + 64 = x^2 - 64
To solve for x, we'll bring all terms to one side of the equation:
X^2 - x^2 + 12x + 64 + 64 = 0
Simplify the equation further:
X^2 - x^2 + 12x + 128 = 0
Now, notice that X^2 - x^2 can be factored as (X + x)(X - x). So, we can rewrite the equation as:
(X + x)(X - x) + 12x + 128 = 0
Now, let's try to solve for x:
(X + x)(X - x) + 12x + 128 = 0
At this point, we don't have enough information to find a specific numerical solution for x because we have two variables, X and x. It's unclear whether these two variables are related or independent, and without additional context or information, we cannot proceed further.
If you have more context or additional equations, please provide them, and I'll be happy to help you solve the system of equations or find the value of x.


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