Question

Сумма двух чисел равна 200.Сумма 61% первого числа и 91 % второго числа равна 152.Найти наименьшее из исходных чисел.

Answer 1

{ a + b = 200
{ 0,61a + 0,91b = 152

{ a = 200 - b
{ 0,61(200 - b) + 0,91b = 152

122 - 0,61b + 0,91b = 152
0,3b = 30
b = 100            a = 200 - b = 200 - 100 = 100

Ответ: {100; 100}

Answer 2

Пусть х большее , а у меньшее число, тогда по условию:
х+у=200;⇒х=200-у.
0,61х+0,91у=152 ⇒х=(152-0,91у)/0,61
Приравняем обе части:
200-у=(152-0,91у)/0,61
0,61(200-у)=152-0,91у
122-0,61у=152-0,91у
0,3у=30
у=100 
х=200-100=100
т.е х=у оба числа равны.
Ответ: 100 первое и 100 второе число.

Answer 3

Let's denote the two numbers as x and y. We are given the following information:

1. x + y = 200 (Sum of the two numbers is 200)
2. 0.61x + 0.91y = 152 (61% of the first number plus 91% of the second number is 152)

To find the smallest of the two numbers, we can set up a system of equations and solve it. Here's how:

Step 1: Express one of the variables in terms of the other from the first equation. x = 200 - y

Step 2: Substitute this expression for x into the second equation. 0.61(200 - y) + 0.91y = 152

Step 3: Solve for y. 122 - 0.61y + 0.91y = 152 0.3y = 152 - 122 0.3y = 30 y = 30 / 0.3 y = 100

Step 4: Now that we have the value of y, we can find the value of x from the first equation. x = 200 - y x = 200 - 100 x = 100

So, the two numbers are x = 100 and y = 100. The smallest of these two numbers is 100.