Question

9+1>d+9 если d= сравнить не вычесляя .при каких числовых значениях буквы неравенства верны

Answer 1

При d принадлежащем от -бесконечности;до 1

(-°°;1)

Answer 2

To compare the inequality without calculating, let's analyze it step by step.

The given inequality is: 9 + 1 > d + 9

First, we can simplify both sides of the inequality: 10 > d + 9

Next, to isolate the variable 'd' on one side, we can subtract 9 from both sides: 10 - 9 > d

Now, we have: 1 > d

So, the inequality states that 1 is greater than 'd'.

Now, let's see for which numerical values of 'd' the inequality is true:

1. If 'd' is any value less than 1, the inequality will be true, as any number less than 1 will be smaller than 1.

For example:

• If d = 0, then 1 > 0 (True)
• If d = -5, then 1 > -5 (True)

2. If 'd' is equal to 1, the inequality will be false, as 1 is not greater than itself.

For example:

• If d = 1, then 1 > 1 (False)

3. If 'd' is any value greater than 1, the inequality will be false, as any number greater than 1 will not be smaller than 1.

For example:

• If d = 2, then 1 > 2 (False)
• If d = 100, then 1 > 100 (False)

To summarize, the inequality 9 + 1 > d + 9 is true when 'd' is any value less than 1 (d < 1), and it is false when 'd' is equal to 1 or any value greater than 1 (d ≥ 1).