Question

2х+3у=1323х-6=4у решите

Answer 1

2х+3у=132

3х-4у=6

Первое уравнение умножим на 3,второе на 2

6х+9у=396

6х-8у=12

От второго отнимем первое получим -17у=-384

У=22,3  отсюда подставляешь на первое ур получишь х

Answer 2

To solve the system of equations, we'll use the method of substitution or elimination. However, there seems to be a typo in the second equation you provided. I believe it should be "2x - 6 = 4y" instead of "2x-6=4у". Let's assume that's the case and solve the system:

1. 2x + 3y = 13
2. 2x - 6 = 4y

We can use the second equation to solve for x in terms of y:

2x = 4y + 6 x = (4y + 6) / 2 x = 2y + 3

Now, we can substitute this expression for x into the first equation:

2(2y + 3) + 3y = 13 4y + 6 + 3y = 13 7y + 6 = 13 7y = 13 - 6 7y = 7 y = 1

Now that we have the value of y, we can find the corresponding value of x using either of the original equations. Let's use the second equation for this:

2x - 6 = 4(1) 2x - 6 = 4 2x = 4 + 6 2x = 10 x = 10 / 2 x = 5

So, the solution to the system of equations is x = 5 and y = 1.