Question

1)14x+27=6562)81y-38y=645

Answer 1

14x+27=656
14x=656-27
14x=629
x=44.92 или 45(если надо округлить)

81y-38y=645
42y+645
y=645/42
y=15.35

Answer 2

To solve these equations, we need to find the values of x and y that satisfy each equation. Let's go step by step:

1. 14x + 27 = 656

To solve for x, we need to isolate it on one side of the equation.

Step 1: Get rid of the constant term on the left side by subtracting 27 from both sides: 14x = 656 - 27 14x = 629

Step 2: Now, isolate x by dividing both sides by 14: x = 629 / 14 x = 44.93 (rounded to two decimal places)

So, the value of x is approximately 44.93.

2. 81y - 38y = 645

To solve for y, follow similar steps:

Step 1: Combine like terms on the left side: 81y - 38y = 43y

Step 2: Now, we have: 43y = 645

Step 3: Finally, isolate y by dividing both sides by 43: y = 645 / 43 y = 15

So, the value of y is 15.

The solutions to the equations are:

1. x ≈ 44.93
2. y = 15