Question

(4y+6)(1,8-0,2y)=0 как ришить

Answer 1

4у + 6 =0-(1,8-0,2у)
4у+6=0,2у-1,8
4у-0,2у=-1,8-6
3,8у= -7,8
у = две целых одна девяднадцатая

Answer 2

To solve the equation $(4y+6)(1.8-0.2y)=0$, we need to find the values of $y$ that make the equation true.

When we have a product equal to zero, one of the factors (or both) must be equal to zero. So, we set each factor equal to zero and solve for $y$:

1. Set $4y+6=0$: $4y = -6$ $y = \frac{-6}{4}$ $y = -\frac{3}{2}$

2. Set $1.8 - 0.2y = 0$: $-0.2y = -1.8$ Divide both sides by -0.2: $y = \frac{-1.8}{-0.2}$ $y = 9$

Now we have two solutions for $y$: $y = -\frac{3}{2}$ and $y = 9$. These are the values that satisfy the given equation $(4y+6)(1.8-0.2y)=0$.