Question

Lg(x+10)>1 решите неравенство

Answer 1

$log_{10}$(x : 10) > 1
$log_{10} (x+10) >1,x > - 10 x + 10 > [tex] 10^{1}$
x + 10 > 10
x > 0,x > - 10
X ∈ (0, + ∞)
x > 0

Answer 2

To solve the inequality $lg(x+10) > 1$, we need to find the values of $x$ that make the inequality true.

First, let's clarify that $lg$ stands for the base-10 logarithm, which is often denoted as $\log_{10}$. The inequality can be rewritten as:

$\log_{10}(x+10) > 1$

Now, recall that the logarithm function $\log_{10}(x)$ represents the exponent to which we raise 10 to get $x$. So, when we have $\log_{10}(x+10) > 1$, it means that $x+10$ must be greater than 10 raised to the power of 1, which is 10.

Thus, the inequality becomes:

$x + 10 > 10$

Now, let's solve for $x$:

$x > 10 - 10$

$x > 0$

So, the solution to the inequality $lg(x+10) > 1$ is $x > 0$.