Question

X1+x2-x3=2-2x1+x2+x3=3x1+x2+x3=6

Answer 1

Решить?Или что то другое?

Answer 2

To solve the system of equations, we can use various methods, such as substitution or elimination. Since the system has three equations and three variables, it is possible to find a unique solution.

Let's use the elimination method to solve the system:

Given the system of equations:

1. x1 + x2 - x3 = 2
2. -2x1 + x2 + x3 = 2
3. 3x1 + x2 + x3 = 6

Step 1: Add the first and second equations to eliminate x1: (x1 + x2 - x3) + (-2x1 + x2 + x3) = 2 + 2 -x1 + 2x2 = 4 x2 - x1 = 4 (Equation A)

Step 2: Add the second and third equations to eliminate x3: (-2x1 + x2 + x3) + (3x1 + x2 + x3) = 2 + 6 4x2 = 8 x2 = 2 (Equation B)

Step 3: Substitute the value of x2 from Equation B into Equation A: x2 - x1 = 4 2 - x1 = 4 x1 = 2 - 4 x1 = -2

Step 4: Now that we have x1 and x2, we can find x3 using any of the original equations. Let's use the first equation: x1 + x2 - x3 = 2 -2 + 2 - x3 = 2 -x3 = 2 - 2 -x3 = 0 x3 = 0

So the solution to the system of equations is: x1 = -2 x2 = 2 x3 = 0