Question

5x-20x^2=0x^2-32=0-x^2-7x-15=0

Answer 1

5х-20х²=0
5х(1-4х)=0
х1=0
х2=¼

х²-32=0
(х-4✓32)(х+4✓2)=0
х¹‘²=±4✓2

-x²-7x-15=0
х²+7х+15=0
D=3,5²-4•15<0
действительных корней нет

Answer 2

It appears that you've written three different equations. Let's solve each equation step by step:

1. 5x - 20x^2 = 0

To solve this equation, let's factor out the common term x:

x(5 - 20x) = 0

Now, set each factor to zero and solve for x:

1. x = 0
2. 5 - 20x = 0 20x = 5 x = 5/20 x = 1/4

So, the solutions to the first equation are x = 0 and x = 1/4.

2. 0x^2 - 32 = 0

This equation is a linear equation with no x^2 term. Let's solve it:

-32 = 0

This equation has no solutions. There is no value of x that satisfies this equation.

3. -x^2 - 7x - 15 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula. Let's factor it:

(-x - 5)(x + 3) = 0

Now, set each factor to zero and solve for x:

1. -x - 5 = 0 -x = 5 x = -5

2. x + 3 = 0 x = -3

So, the solutions to the third equation are x = -5 and x = -3.

In summary, the solutions to the three equations are as follows:

1. x = 0 and x = 1/4
2. No solution
3. x = -5 and x = -3