Question

4/9 = ?/36 11/18 = ?/36 7/12 = ?/36 8/72 = ?/36 12/108 = ?/36 130/360 = ?/36

Answer 1

16/36
22/36
21/36
4/36
4/36
13/36

Answer 2

1. 16/36, 2. 22/36, 3. 21/36, 4. 16/36, 5. 4/36, 6. 13/36

Answer 3

To solve the equations, we need to find the value of the missing numerator in each case. The idea is to set up proportions and solve for the unknown numerator. We can do this by cross-multiplication. Let's calculate the missing numerators for each equation:

1. 4/9 = ?/36 Cross-multiplying: 4 * 36 = 9 * ? Solving for ?: ? = (4 * 36) / 9 = 16

2. 11/18 = ?/36 Cross-multiplying: 11 * 36 = 18 * ? Solving for ?: ? = (11 * 36) / 18 = 22

3. 7/12 = ?/36 Cross-multiplying: 7 * 36 = 12 * ? Solving for ?: ? = (7 * 36) / 12 = 21

4. 8/72 = ?/36 Cross-multiplying: 8 * 36 = 72 * ? Solving for ?: ? = (8 * 36) / 72 = 4

5. 12/108 = ?/36 Cross-multiplying: 12 * 36 = 108 * ? Solving for ?: ? = (12 * 36) / 108 = 4

6. 130/360 = ?/36 Cross-multiplying: 130 * 36 = 360 * ? Solving for ?: ? = (130 * 36) / 360 = 13

So, the missing numerators in the given equations are as follows:

1. 4/9 = 16/36
2. 11/18 = 22/36
3. 7/12 = 21/36
4. 8/72 = 4/36
5. 12/108 = 4/36
6. 130/360 = 13/36