Question

(2х-1,2)(3х-0,3)=0 реш.уравнение

Answer 1

(2х-1,2)(3х-0,3)=0

6х^2-0,6х-3,6х+0,36=0

6х^2-4,2х+0,36=0

Д=17,64-8,64=9

Х1,2=4,2±3/12

Х1=4,2+3/12=0,6

Х2=4,2-3/12=0,1

Answer 2

(2х-1,2)(3х-0,3)=0
$(2x - \frac{6}{5} )(3x - \frac{3}{10} ) = 0$

$2x - \frac{6}{5} = 0$

$2x = \frac{6}{5}$

$x1= \frac{3}{5}$

$3x - \frac{3}{10} = 0$

$x2 = \frac{1}{10}$

Ответ:
$x1 = \frac{3}{5}$

$x2 = \frac{1}{10}$

Answer 3

To solve the equation "(2x-1)(3x-0.3) = 0," we need to find the values of x that make the equation true. To do that, we set each factor equal to zero and solve for x:

1. Set (2x - 1) = 0: 2x - 1 = 0 Add 1 to both sides: 2x = 1 Divide both sides by 2: x = 1/2

2. Set (3x - 0.3) = 0: 3x - 0.3 = 0 Add 0.3 to both sides: 3x = 0.3 Divide both sides by 3: x = 0.3/3 x = 0.1

The solutions to the equation are x = 1/2 and x = 0.1.