Question

1) X^2+3x-2=0 2) -x^2-3x+2=0

Answer 1

1) X^2+3x-2=0     Д=9+8=17  х1=(-3+sqrt(17))/2   х2=(-3-sqrt(17))/2)    

2) -x^2-3x+2=0

Answer 2

To find the solutions for each quadratic equation, we can use the quadratic formula. The quadratic formula states that for any quadratic equation in the form of ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Let's apply the quadratic formula to each of the given equations:

1. x^2 + 3x - 2 = 0 Here, a = 1, b = 3, and c = -2.

x = (-3 ± √(3^2 - 4*1*(-2))) / 2*1 x = (-3 ± √(9 + 8)) / 2 x = (-3 ± √17) / 2

So, the solutions for this equation are: x = (-3 + √17) / 2 and x = (-3 - √17) / 2

2. -x^2 - 3x + 2 = 0 Here, a = -1, b = -3, and c = 2.

x = (-(-3) ± √((-3)^2 - 4*(-1)*2)) / 2*(-1) x = (3 ± √(9 + 8)) / -2 x = (3 ± √17) / -2

So, the solutions for this equation are: x = (3 + √17) / -2 and x = (3 - √17) / -2

Note that both equations have real solutions since the discriminant (b^2 - 4ac) in each case is positive.