Question

9

Answer 1

${(x - 1)}^{2} \leqslant 9 \\ \sqrt{ {(x - 1)}^{2} } \leqslant \sqrt{9} \\ |x - 1| \leqslant 3 \\ \\ \\ x - 1 \leqslant 3 \\ x - 1 \geqslant - 3 \\ \\ x \leqslant 4 \\ x \geqslant - 2$
Длина интервала - разница между значением крайней правой и крайней левой точками. Т.е. длина интервала [-2;4] = 4 - (-2)= 4 + 2 = 6
Ответ: 6.

Answer 2

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