Question

-6ц2\3а-1\6+4ц3\4а- 1\12

Answer 1

Ответ:

-6ц(2/3а-1/6)+4ц(3/4а-1/12)= -6*2/3а+6*1/6+4*3/4а-4*1/12=

=-4а+1+3а-1/3=-а+2/3

Пошаговое объяснение:

Answer 2

Ответ:

Пошаговое объяснение:

-6 2\3а-1\6+4 3\4а- 1\12=(-6 2/3a+4 3/4a)-(1/6+1/12)=(-6 8/12a+4 9/12a)-(2/12+1/12)=-1 11/12a-1/4

Answer 3

It seems like the expression you provided contains some symbols that are not standard mathematical notation. Specifically, the symbols "ц" and "а" are not recognizable as mathematical operators or variables in conventional notation.

If you can clarify the meaning of these symbols or provide the intended expression using standard mathematical notation (e.g., +, -, *, /, parentheses, variables like x or y), I'd be more than happy to help you solve or simplify the expression.