Question

( 9-2 2/3 * 2 1/7) * 21/46По действиям

Answer 1

$1)2 \frac{2}{3} \times 2 \frac{1}{7} = \frac{8 \times 15}{3 \times 7} = \frac{40}{7} = 5 \frac{5}{7} \\ 2)9 - 5 \frac{5}{7} = 8 \frac{7}{7} - 5 \frac{5}{7} = 3 \frac{2}{7} \\ 3)3 \frac{2}{7} \times \frac{21}{46} = \frac{23 \times 21}{7 \times 46} = \frac{3}{2} = 1 \frac{1}{2}$

Answer 2

To solve the expression, follow the order of operations (PEMDAS/BODMAS):

P: Parentheses/Brackets E: Exponents/Orders MD: Multiplication and Division (left to right) AS: Addition and Subtraction (left to right)

Let's start step by step:

1. Solve inside the parentheses first: (9 - 2 2/3 * 2 1/7)

2 2/3 can be written as an improper fraction: (2 * 3 + 2) / 3 = 8/3 2 1/7 can be written as an improper fraction: (2 * 7 + 1) / 7 = 15/7

Now the expression becomes: (9 - 8/3 * 15/7)

2. Next, perform the multiplication: 8/3 * 15/7 = (8 * 15) / (3 * 7) = 120 / 21

Now the expression becomes: (9 - 120 / 21)

3. Perform the division: 120 / 21 = 40 / 7

Now the expression becomes: (9 - 40 / 7)

4. Perform the subtraction: (9 - 40/7) = (63/7 - 40/7) = 23/7

Now the expression becomes: (23/7)

5. Finally, multiply by 21/46: (23/7) * 21/46

Now, perform the multiplication: (23 * 21) / (7 * 46) = 483 / 322

So the final result is 483/322.