Question

321-( х÷11+29)×6=105

Answer 1

321 - (х : 11 + 29) · 6 = 105

(х : 11 + 29) · 6 = 321 - 105

(х : 11 + 29) · 6 = 216

х : 11 + 29 = 216 : 6

х : 11 + 29 = 36

х : 11 = 36 - 29

х : 11 = 7

х = 7 · 11

х = 77

Проверка:

321 - (77 : 11 + 29) · 6 = 105

321 - 36 · 6 = 105

321 - 216 = 105

105 = 105

Answer 2

321-(x÷11+29)×6=105
321-(6/11x+174)=105
321-6/11x-174=105
147-6/11x=105
1617-6x=1155
x=77

Answer 3

To solve the equation, let's follow the order of operations (PEMDAS/BODMAS) to simplify the expression:

1. Perform division (÷) first: 321 - (х ÷ 11 + 29) × 6 = 105

2. Solve the expression inside the parentheses: х ÷ 11 + 29 = ???

We'll need more information to proceed since the value of "х" is not given in the equation. Without knowing the value of "х," we cannot calculate the result of the expression inside the parentheses, and therefore, we cannot solve the equation.

If you have the value of "х," please provide it, and I'll be happy to help you solve the equation.