Question

Y = -x² +4; y =0 С решением

Answer 1

-x² +4=0
-x²=0-4
-x²=4
x²=-4
уравнение тождественное равн.

Answer 2

To find the solution to the system of equations, we need to find the value(s) of 'x' that satisfy both equations simultaneously. The system of equations is:

1. Y = -x² + 4
2. Y = 0

Since both equations have 'Y' in them, we can equate them since they both represent the same value of 'Y':

-x² + 4 = 0

To solve this quadratic equation for 'x', we can follow these steps:

Step 1: Move the constant term (4) to the other side of the equation: -x² = -4

Step 2: To solve for 'x', divide both sides by -1 (or multiply both sides by -1): x² = 4

Step 3: Take the square root of both sides to eliminate the square: x = ±√4

Step 4: Simplify the square root: x = ±2

The solutions for 'x' are x = 2 and x = -2.

So, the system of equations has two solutions: (x = 2, y = 0) and (x = -2, y = 0).