Question

0,2(x-8)=0,49(x-3)7x-5=5x+7-3x=x=42x-1=4x+3Даю 19б

Answer 1

0,2(x-8)=0,49(x-3)
0,2x-1,6=0,49x-1,47
0,2x-0,49x=1,6+1,47
-0,29x=0,13
x=-13/29 (дробь)

7x-5=5x+7
7х-5х=7+5
2х=12
х=6

-3x=x=4
-3х-х=4
-4х=4
х=-1

2x-1=4x+3
2х-4х=3+1
-2х=4
х=-2

Answer 2

It seems like you've provided a series of equations and an expression with some instructions. Let's go through each step:

1. 0.2(x-8) = 0.49(x-3)

To solve this equation, we need to find the value of x that satisfies the equation. Let's solve it step by step:

0.2(x-8) = 0.49(x-3)

First, distribute the constants:

0.2x - 1.6 = 0.49x - 1.47

Next, move all the terms containing x to one side of the equation and the constants to the other side:

0.2x - 0.49x = -1.47 + 1.6

Now, combine like terms:

-0.29x = 0.13

Finally, isolate x by dividing both sides by -0.29:

x = 0.13 / -0.29

x ≈ -0.448

2. 7x - 5 = 5x + 7 - 3x

To solve this equation, we again need to find the value of x that satisfies it. Let's simplify it step by step:

7x - 5 = 5x + 7 - 3x

First, combine like terms on the right side:

7x - 5 = 2x + 7

Next, move all the terms containing x to one side of the equation and the constants to the other side:

7x - 2x = 7 + 5

Now, combine like terms:

5x = 12

Finally, isolate x by dividing both sides by 5:

x = 12 / 5

x = 2.4

3. x = 42x - 1 = 4x + 3

This looks like two equations:

1. x = 42x - 1
2. 42x - 1 = 4x + 3

Let's solve each equation separately:

1. x = 42x - 1

Move all the terms containing x to one side and the constant to the other side:

x - 42x = -1

Combine like terms:

-41x = -1

Isolate x by dividing both sides by -41:

x = -1 / -41

x ≈ 0.0244

2. 42x - 1 = 4x + 3

Move all the terms containing x to one side and the constant to the other side:

42x - 4x = 3 + 1

Combine like terms:

38x = 4

Isolate x by dividing both sides by 38:

x = 4 / 38

x ≈ 0.1053

It seems there was an inconsistency in your provided equations. None of the solutions match exactly. If you could clarify the instructions or the equations, I'd be happy to assist further!