Question

6карандашей стоят на 30рублей дешевое чем 3ручки и 3карандаша.На сколько рублей карандаш дешевле ручки?

Answer 1

Запишим решение и ответ

Решение: составим уравнение согласно условиям задачи 6 (кар) + 30 = 3 (ручки) + 3 (кар). Тогда:

3 (ручки) - 3 (кар) = 30

1 (ручка) - 1 (кар) = 10.

Ответ: на 10 р.
Удачи )

Answer 2

Let's break down the information given in the problem:

Let's assume the cost of one pencil (карандаш) is P rubles. The cost of one pen (ручка) is R rubles.

According to the problem, we have the following information:

1. 6 pencils cost 30 rubles: 6P = 30
2. 3 pens and 3 pencils cost more than 30 rubles: 3R + 3P > 30

Now, let's solve for the cost of one pencil (P) using the first equation:

6P = 30 P = 30 / 6 P = 5 rubles

Now that we know one pencil costs 5 rubles, let's solve for the cost of one pen (R) using the second equation:

3R + 3P > 30 3R + 3(5) > 30 3R + 15 > 30 3R > 30 - 15 3R > 15 R > 5

Since the total cost of 3 pens (3R) is greater than 15 rubles and one pen (R) is more expensive than 5 rubles, the cost of one pen must be more than 5 rubles.

Finally, let's find out how much cheaper a pencil (карандаш) is compared to a pen (ручка):

Difference = Cost of one pen (R) - Cost of one pencil (P) Difference = R - P Difference > 5 - 5 Difference > 0

So, a pencil (карандаш) is cheaper than a pen (ручка) by at least 0 rubles, or in other words, there is no price difference between the two based on the given information. However, it is worth noting that this result may seem unusual, and it's possible that there might be a typo or an error in the problem statement.