Question

Решить: (b-4)(b+4) (2a+b)(2a-b) x в квадрате+10x+25 x в квадрате+6x+9 4x в квадрате+20x+25

Answer 1

b^2-16

4a^2-b^2

(х+5)^2

(х+3)^2

(2х+5)^2

Answer 2

Ответ////////////////////

Answer 3

To solve the expression you provided, let's simplify it step by step:

1. (b-4)(b+4): This is the difference of squares, so it simplifies to b^2 - 16.

2. (2a+b)(2a-b): This is also the difference of squares, so it simplifies to (2a)^2 - b^2, which is 4a^2 - b^2.

3. x^2 + 10x + 25: This is a perfect square trinomial, and it can be factored as (x + 5)^2.

4. x^2 + 6x + 9: This is also a perfect square trinomial, and it can be factored as (x + 3)^2.

5. 4x^2 + 20x + 25: This is a perfect square trinomial, and it can be factored as (2x + 5)^2.

Now, let's put all the simplified expressions together:

((b-4)(b+4)) * ((2a+b)(2a-b)) * (x^2 + 10x + 25) * (x^2 + 6x + 9) * (4x^2 + 20x + 25)

(b^2 - 16) * (4a^2 - b^2) * (x + 5)^2 * (x + 3)^2 * (2x + 5)^2

Now, we can combine the factors using the properties of multiplication:

(b^2 - 16) * (4a^2 - b^2) * (x + 5)^2 * (x + 3)^2 * (2x + 5)^2

Next, we can further simplify the expression if necessary. If you have specific values for 'a' and 'b' or any other specific instructions, please provide them, and I can continue to help you further.