Question

10•(5 7/10-3 3/7)= (3 4/15+4 5/6)•(3 17/18-2 5/9)=

Answer 1

Ответ:

Пошаговое объяснение:

10•(5 7/10-3 3/7)=22 5/7

5 7/10-3 3/7=5 49/70-3 30/70=2 19/70

10*2 19/70=10*159/70=159/7=22 5/7

(3 4/15+4 5/6)•(3 17/18-2 5/9)=11 1/4

3 4/15+4 5/6=3 8/30+4 25/30=8 1/10

3 17/18-2 5/9=3 17/18-2 10/18=1 7/18

8 1/10*1 7/18=81/10*25/18=45/4=11 1/4

Answer 2

Let's solve each of these equations step by step:

1. $10 \cdot \left(5 \frac{7}{10} - 3 \frac{3}{7}\right)$

First, let's convert the mixed fractions to improper fractions:

$5 \frac{7}{10} = \frac{57}{10}$

$3 \frac{3}{7} = \frac{24}{7}$

Now, we can perform the subtraction:

$10 \cdot \left(\frac{57}{10} - \frac{24}{7}\right)$

Next, let's find a common denominator, which is 70:

$10 \cdot \left(\frac{57}{10} \cdot \frac{7}{7} - \frac{24}{7} \cdot \frac{10}{10}\right)$

$10 \cdot \left(\frac{399}{70} - \frac{240}{70}\right)$

Now, subtract the fractions:

$10 \cdot \frac{159}{70}$

Finally, perform the multiplication:

$10 \cdot \frac{159}{70} = \frac{1590}{70} = 22 \frac{10}{70} = 22 \frac{1}{7}$

So, $10 \cdot \left(5 \frac{7}{10} - 3 \frac{3}{7}\right) = 22 \frac{1}{7}$.

2. $(3 \frac{4}{15} + 4 \frac{5}{6}) \cdot \left(3 \frac{17}{18} - 2 \frac{5}{9}\right)$

Let's convert the mixed fractions to improper fractions:

$3 \frac{4}{15} = \frac{49}{15}$

$4 \frac{5}{6} = \frac{29}{6}$

$3 \frac{17}{18} = \frac{59}{18}$

$2 \frac{5}{9} = \frac{23}{9}$

Now, we can perform the additions and subtractions:

$\left(\frac{49}{15} + \frac{29}{6}\right) \cdot \left(\frac{59}{18} - \frac{23}{9}\right)$

Let's find a common denominator for each set of fractions:

For the first set of fractions (inside the first parentheses), the common denominator is 30:

$\left(\frac{49}{15} \cdot \frac{2}{2} + \frac{29}{6} \cdot \frac{5}{5}\right) \cdot \left(\frac{59}{18} - \frac{23}{9}\right)$

$\left(\frac{98}{30} + \frac{145}{30}\right) \cdot \left(\frac{59}{18} - \frac{23}{9}\right)$