Question

Решить 3/4*7/8-3/4*(7/8-2/3)

Answer 1

$\frac34\cdot\frac78-\frac34\cdot\left(\frac78-\frac23\right)=\frac34\cdot\frac78-\frac34\cdot\frac78+\frac34\cdot\frac23=\frac12$

Answer 2

To solve the expression, follow the order of operations (PEMDAS/BODMAS):

1. Parentheses/Brackets
2. Exponents/Orders (not present in this expression)
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

Let's proceed step by step:

1. Solve the expression inside the parentheses first: 7/8 - 2/3

To find a common denominator between 8 and 3, we can use the product of the two denominators, which is 8 * 3 = 24.

Now, convert both fractions to have a denominator of 24:

(7/8) * (3/3) = 21/24 (2/3) * (8/8) = 16/24

So, 7/8 - 2/3 becomes 21/24 - 16/24:

21/24 - 16/24 = 5/24

2. Now, rewrite the original expression with the simplified part: 3/4 * 7/8 - 3/4 * (5/24)

3. Next, perform the multiplications:

3/4 * 7/8 = (3 * 7) / (4 * 8) = 21/32

3/4 * 5/24 = (3 * 5) / (4 * 24) = 15/96 = 5/32

4. Finally, subtract the result:

21/32 - 5/32 = (21 - 5) / 32 = 16/32 = 1/2

So, the final solution to the expression is 1/2.