Question

1)10 6/10-(7 3/10-y) =4 9/10 2)3 4/9-(x-1 7/9)=2 2/9 3)17 18/35-(n+4 23/35) =9 12/45

Answer 1

Ответ:

Пошаговое объяснение:

1)10 6/10-(7 3/10-y) =4 9/10

10 6/10-7 3/10+y=4 9/10

y=4 9/10+7 3/10-10 6/10

y=1 6/10=1 3/5

2)3 4/9-(x-1 7/9)=2 2/9

3 4/9-x+1 7/9=2 2/9

x=3 4/9+1 7/9-2 2/9

x=2 9/9=3

3)17 18/35-(n+4 23/35) =9 12/35

17 18/35-n-4 23/35 =9 12/35

n=17 18/35-4 23/35-9 12/35

n=3 18/35

Answer 2

To solve each of the given equations, we'll perform the necessary operations step by step. Let's solve them one by one:

1. $10 \frac{6}{10} - (7 \frac{3}{10} - y) = 4 \frac{9}{10}$

Step 1: Simplify the expression inside the parentheses: $7 \frac{3}{10} - y = 7.3 - y$

Step 2: Subtract the expression inside the parentheses from $10 \frac{6}{10}$: $10 \frac{6}{10} - (7.3 - y) = 10.6 - 7.3 + y = 3.3 + y$

Step 3: Now, set the expression equal to $4 \frac{9}{10}$ and solve for $y$: $3.3 + y = 4 \frac{9}{10}$

Step 4: Subtract $3.3$ from both sides to isolate $y$: $y = 4 \frac{9}{10} - 3.3$

Step 5: Perform the subtraction on the right side: $y = 4.9 - 3.3 = 1.6$

So, the solution for $y$ is $y = 1.6$.

2. $3 \frac{4}{9} - (x - 1 \frac{7}{9}) = 2 \frac{2}{9}$

Step 1: Simplify the expression inside the parentheses: $x - 1 \frac{7}{9} = x - \left(1 + \frac{7}{9}\right) = x - \frac{16}{9}$

Step 2: Subtract the expression inside the parentheses from $3 \frac{4}{9}$: $3 \frac{4}{9} - (x - \frac{16}{9}) = 3 \frac{4}{9} - x + \frac{16}{9} = \frac{31}{9} - x$

Step 3: Now, set the expression equal to $2 \frac{2}{9}$ and solve for $x$: $\frac{31}{9} - x = 2 \frac{2}{9}$

Step 4: Subtract $\frac{31}{9}$ from both sides to isolate $x$: $x = \frac{31}{9} - 2 \frac{2}{9}$

Step 5: Perform the subtraction on the right side: $x = \frac{31}{9} - \frac{20}{9} = \frac{11}{9}$

So, the solution for $x$ is $x = \frac{11}{9}$.

3. $17 \frac{18}{35} - (n + 4 \frac{23}{35}) = 9 \frac{12}{45}$

Step 1: Simplify the expression inside the parentheses: $n + 4 \frac{23}{35} = n + \frac{158}{35}$

Step 2: Subtract the expression inside the parentheses from $17\frac{18}{35}$ 0 0