Question

B1=3 q=2 s6-?геметрия прогрессия

Answer 1

B6=b1*q^5=3*32=96

S6=(3-96*2)/(1-2)=(3-192)/(-1)=189

Answer 2

It appears that you have provided some incomplete information, and it's not entirely clear what you are asking. However, I will try to interpret your question and provide some insights about arithmetic progression.

An arithmetic progression (AP) is a sequence of numbers in which the difference between any two consecutive terms is constant. The constant difference is called the "common difference," denoted by 'd.' The general form of an arithmetic progression is:

a, a + d, a + 2d, a + 3d, ...

where 'a' is the first term and 'd' is the common difference.

From the information given, we have:

B1 = 3 (This is the first term of the arithmetic progression) q = 2 (This is likely a typo, as 'q' is usually used to denote the common ratio in a geometric progression, not in an arithmetic progression.)

If you meant to provide the common difference as 'd' rather than 'q', and you want to find the sixth term 's6' of the arithmetic progression, we'll need the value of 'd' to proceed.

For example, if 'd' is 4 (assuming 'q' was meant to be the common difference), then the arithmetic progression would be:

3, 7, 11, 15, 19, s6

In this case, the sixth term 's6' would be 19 + 4 = 23.

If you could clarify your question or provide more information, I'd be happy to help further!