Question

2a-3(a-2)=-4. 5m+4(m-3)=24

Answer 1

1) 2a-3(a-2)=-4

2a-3a+6=-4

-a+6=-4

-a=-4-6

-a=-10

a=10

2) 5m+4(m-3)=24

9m-12=24

9m=24+12

9m=36

m=4

Answer 2

2a-3(a-2)=-4

2a-3a+6=-4

-a=-10

a=10

5m+4(m-3)=24

5m+4m-12=24

9m=36

m=4

Answer 3

Let's solve the given equations step-by-step:

1. Solve 2a - 3(a - 2) = -4:

To solve this equation, you need to apply the distributive property first and then simplify further.

Step 1: Distribute the -3 across (a - 2): 2a - 3a + 6 = -4

Step 2: Combine the like terms (2a and -3a) on the left side of the equation: (2a - 3a) + 6 = -4 -1a + 6 = -4

Step 3: Move the constant term (6) to the right side of the equation by subtracting it from both sides: -1a = -4 - 6 -1a = -10

Step 4: To solve for 'a,' divide both sides of the equation by -1: a = -10 / -1 a = 10

So, the solution for the first equation is: a = 10.

2. Solve 5m + 4(m - 3) = 24:

Again, we will use the distributive property and follow the same steps as in the first equation.

Step 1: Distribute the 4 across (m - 3): 5m + 4m - 12 = 24

Step 2: Combine the like terms (5m and 4m) on the left side of the equation: (5m + 4m) - 12 = 24 9m - 12 = 24

Step 3: Move the constant term (12) to the right side of the equation by adding it to both sides: 9m = 24 + 12 9m = 36

Step 4: To solve for 'm,' divide both sides of the equation by 9: m = 36 / 9 m = 4

So, the solution for the second equation is: m = 4.