Question

1). 1/4x+1/x=3/8. 2). 1/x+ 1/3/4x=7/12 20 баллов

Answer 1

Ответ:

1.Приводим к одному общему знаменателю-4х*х*8,теперь к каждой дроби добавляем недостающего знаменателя,получим

8х+32х=12х^2

-12x^2+40x=0

x(12x-40)=0

x1=0

12x-40=0

12x=40

x2=40/12

x2=3 1/3

Пошаговое объяснение:

Answer 2

To solve the given equations, we need to find the value of 'x'. Let's solve each equation step-by-step:

1. 1/(4x) + 1/x = 3/8

To add the fractions, we need a common denominator, which is 8x. So, we'll rewrite the equation with the common denominator:

(1 * 2 + 1 * 8)/(8x) = 3/8

Now, simplify the left side:

(2 + 8)/(8x) = 3/8

10/(8x) = 3/8

To solve for 'x', cross-multiply:

10 * 8 = 3 * 8x

80 = 24x

Now, isolate 'x' by dividing both sides by 24:

x = 80/24

x = 20/6

2. 1/x + 1/(3/4)x = 7/12

First, simplify the second term by multiplying the fraction (3/4) by x:

1/x + 1 * 4/3x = 7/12

Now, find the common denominator, which is 12x:

(1 * 12 + 4)/(12x) = 7/12

Simplify the left side:

(12 + 4)/(12x) = 7/12

16/(12x) = 7/12

To solve for 'x', cross-multiply:

16 * 12 = 7 * 12x

192 = 84x

Now, isolate 'x' by dividing both sides by 84:

x = 192/84

x = 16/7

To summarize the results:

1. x = 20/6 or 10/3

2. x = 16/7