Question

(3х-1) (2х+1) > (2х-1) (2+3х)​

Answer 1

Вот так вот ) надеюсь понятно

Answer 2

To solve the inequality (3x - 1)(2x + 1) > (2x - 1)(2 + 3x), we need to first expand both sides and then simplify the inequality:

Expanding the left side: (3x - 1)(2x + 1) = 6x^2 + 3x - 2x - 1 = 6x^2 + x - 1

Expanding the right side: (2x - 1)(2 + 3x) = 2x(2 + 3x) - 1(2 + 3x) = 4x + 6x^2 - 2 - 3x = 6x^2 + x - 2

Now, the inequality becomes: 6x^2 + x - 1 > 6x^2 + x - 2

Notice that the 6x^2 and x terms are the same on both sides, so they cancel out. We are left with:

-1 > -2

This inequality is always true. No matter what value of x we choose, -1 will always be greater than -2.

So, the solution to the inequality is all real numbers, or in interval notation, (-∞, +∞).