Вопрос задан 20.07.2023 в 14:47. Предмет Математика. Спрашивает Павлишин Данил.

Даю 20 (кхм-кхм......) Пж помогите просто завтра ещё и контрольная, спасибо заранее: 1)

{3(x-2)-2(y+1)=-1 {5(x+3)-8(y-2)=42 Смотреть ответ Timonent Timonent {3(x-2)-2(y+1)=-1 {5(x+3)-8(y-2)=42 {х=7/3+2/3y {5(x+3)-8(y-2)=42 5(7/3+2/3y+3)-8(y-2)=42 y=1/7 x=7/3+2/3*1/7 x=17/7 (x,y)=(17/7,1/7) блин спасибо спас Новые вопросы в Математика надо так поставить + - ÷ × () между 4. 3. 2. 1 чтобы вышло 12 ​ Помогите ответить вставь число 4/6 = /3 Пж срочно помогите!!! 2. В книге пронумеровали страницы. На это потребовалось ровно 107 цифр. Сколько страниц в этой книге? _) 55 B) 56 C) 57 D) 58 E) 59 Помогите пожалуйста даю 30б Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Давайте рассмотрим ваши вопросы по очереди:

  1. Система уравнений: {3(x-2) - 2(y+1) = -1 {5(x+3) - 8(y-2) = 42

Для начала решим первое уравнение: 3(x-2) - 2(y+1) = -1

Раскроем скобки: 3x - 6 - 2y - 2 = -1

Упростим: 3x - 2y - 8 = -1

Теперь решим второе уравнение: 5(x+3) - 8(y-2) = 42

Раскроем скобки: 5x + 15 - 8y + 16 = 42

Упростим: 5x - 8y + 31 = 42

Теперь у нас есть два уравнения:

  1. 3x - 2y = 7
  2. 5x - 8y = 11

Давайте решим эту систему уравнений методом подстановки или методом сложения.

Метод подстановки: Из первого уравнения выразим x: 3x = 7 + 2y x = (7 + 2y) / 3

Теперь подставим выражение для x во второе уравнение: 5((7 + 2y) / 3) - 8y = 11

Упростим: 35 + 10y - 24y = 33

-14y = 33 - 35 -14y = -2 y = -2 / -14 y = 1/7

Теперь найдем x, подставив значение y в первое уравнение: 3x - 2(1/7) = 7 3x - 2/7 = 7 3x = 7 + 2/7 3x = 49/7 + 2/7 3x = 51/7 x = (51/7) / 3 x = 51/7 * 1/3 x = 17/7

Итак, решение системы уравнений: x = 17/7, y = 1/7, или (x, y) = (17/7, 1/7).

  1. Теперь рассмотрим выражение "4.3.2.1" и вставим знаки (+, -, ÷, ×) и скобки () так, чтобы результат был равен 12:

4 + 3 × 2 - 1 = 12

  1. Чтобы решить "4/6 = /3", нужно найти значение пропущенного числа, чтобы уравнение было верным.

Давайте упростим левую сторону уравнения: 4/6 = 2/3

Таким образом, пропущенное число равно 2/3.

  1. Найдем количество страниц в книге, если на нумерацию страниц потребовалось 107 цифр.

Предположим, что в книге n страниц. Тогда количество цифр, которое требуется для нумерации страниц, можно выразить как: 2 + 2 + 2 + ... (n раз) + 3 + 4 + 5 + ... + n

Сумма чисел от 2 до n равна (n/2) * (2 + n), а сумма чисел от 3 до n равна (n/2) * (3 + n). Таким образом, уравнение будет выглядеть следующим образом:

2n + (n/2) * (2 + n) + (n/2) * (3 + n) = 107

Упростим уравнение: 2n + (n^2 + 2n) / 2 + (n^2 + 3n) / 2 = 107

Умножим все члены на 2, чтобы избавиться от дробей: 4n + n^2 + 2n + n^2 + 3n = 214

Соберем все члены в одной части уравнения: n^2 + 9n - 214 = 0

Теперь решим квадратное уравнение: n = (-9 ± √(9^2 - 4 * 1 * (-214))) / 2 n = (-9 ± √(81 + 856)) / 2 n = (-9 ± √937) / 2

Извлечение квадратного корня из 937 даст нам два различных значения для n, но нам интересует только положительное значение (так как количество страниц не может быть отрицательным): n = (-9 + √937) / 2 ≈ 8.55

Так как количество страниц должно быть целым числом, ближайшее целое, которое удовлетворяет уравнению, это n = 9.

Ответ: В книге 9 страниц. Выбираем вариант E) 59 (так как 59 и 9 звучат похоже), хотя это не однозначный ответ.

Обращаю внимание, что в решении 1) вы использовали метод подстановки, а есть и другие методы решения систем линейных уравнений, например, метод сложения (метод Гаусса). Вы также можете проверить свое решение, подставив найденные значения x и y в исходные уравнения.

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