Question

5×X=7+28,63-X=100÷5,A÷48=0÷37×11,A×43=102-51×2​

Answer 1

5х=35

Х=35:5=7

63-X=100÷5,

63-х=20

Х=63-20

Х=43

A÷48=0÷37×11,

А:48=0

А=0*48=0

A×43=102-51×2

А*43=102-102

А*43=0

А=0:43=0

Answer 2

Let's solve each equation step by step:

1. 5×X = 7 + 28 To solve for X, first, combine the numbers on the right side: 5×X = 35

Now, isolate X by dividing both sides by 5: X = 35 ÷ 5 X = 7

2. 63 - X = 100 ÷ 5 First, perform the division on the right side: 63 - X = 20

Now, isolate X by subtracting 63 from both sides: -X = 20 - 63 -X = -43

To solve for X, multiply both sides by -1: X = -(-43) X = 43

3. A ÷ 48 = 0 ÷ 37 × 11 Since any number divided by zero is undefined, this equation has no valid solution. Division by zero is not allowed in mathematics.

4. A × 43 = 102 - 51 × 2 First, perform the multiplication on the right side: A × 43 = 102 - 102

Now, isolate A by subtracting 102 from both sides: A × 43 - 102 = 0

Next, factor out A from the left side: A(43 - 102) = 0

Now, simplify the equation further: A(-59) = 0

To solve for A, divide both sides by -59: A = 0 ÷ (-59) A = 0

So, the solutions for the given equations are: X = 7 X = 43 A = 0