Question

2х в квадрате +3х+1=0​

Answer 1

Пошаговое объяснение:

D=3²-4*2*1=9-8=1

x¹=1-3/2*2=-0.5

x²=-1-3/2*2=-1

Answer 2

Ответ:(-1) , (-1/2)

Пошаговое объяснение:

Answer 3

To solve the quadratic equation 2x^2 + 3x + 1 = 0, we can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In your equation, a = 2, b = 3, and c = 1. Now, let's plug these values into the quadratic formula and solve for x:

x = (-(3) ± √(3^2 - 4 * 2 * 1)) / 2 * 2 x = (-3 ± √(9 - 8)) / 4 x = (-3 ± √1) / 4 x = (-3 ± 1) / 4

Now we have two possible solutions for x:

1. x = (-3 + 1) / 4 x = -2 / 4 x = -1/2

2. x = (-3 - 1) / 4 x = -4 / 4 x = -1

So, the solutions to the equation 2x^2 + 3x + 1 = 0 are x = -1/2 and x = -1.