Question

3:3/3,4+2/2,5×2/1,2×2/1,2-3/5,6​

Answer 1

3÷3/3,4+2/2,5×2/1,2×2/1,2-3/5,6=5(109/1260)

1) 3÷(3/3,4)=3×(3,4/3)=(3×3,4)/3=3,4=(34/10)=17/5;

2) (2/2,5)×(2/1,2)=(2÷(25/10))×(2÷(12/10))=(2÷(5/2))×(2÷(6/5))=(2×(2/5))×(2×(5/6)=(4/5)×(5/3)=(4×5)/(5×3)=4/3;

3) (4/3)×(2/1,2)=(4/3)×(2÷(12/10))=(4/3)×(2×(10/12))=(4/3)×2×(5/6)=(4×2×5)/(3×6)=(4×5)/(3×3)=20/9;

4) (3/5,6)=3÷(56/10)=3÷(28/5)=3×5/28=15/28;

5) (17/5)+(20/9)=(17×9+20×5)/45=(153+100)/45=253/45;

6) (253/45)-(15/28)=(253×28-15×45)/(45×28)=(7084-675)/1260=(6409/1260)=5(109/1260).

Answer 2

To solve the expression 3:3/3,4+2/2,5×2/1,2×2/1,2-3/5,6, let's break it down step by step following the order of operations (PEMDAS/BODMAS).

1. Begin by simplifying the divisions: 3:3/3,4 = (3/3) / 3,4 = 1 / 3,4

2. Next, simplify the additions: 4+2/2,5 = 4 + (2/2,5) = 4 + 0,8

3. Move on to the multiplications: 0,8×2/1,2 = (0,8×2) / 1,2 = 1,6 / 1,2

4. Finally, perform the subtractions: 1,6-3/5,6 = 1,6 - (3/5,6)

Now, let's calculate each step:

1. 1 / 3,4 = 0.2941176470588235 (rounded to 16 decimal places)
2. 4 + 0,8 = 4.8
3. 1,6 / 1,2 = 1.3333333333333333 (rounded to 16 decimal places)

Therefore, the final result of the expression 3:3/3,4+2/2,5×2/1,2×2/1,2-3/5,6 is approximately 1.3333333333333333.